Trapezoidal motion/kinematics calculations - solving for slewing velocity

larsbentley
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I am trying to program some motion control devices which have trapezoidal motion profiles to define a move. I can define the slewing(peak) velocity, accel/decel rates and distance to travel, the the hardware moves a motor the appropriate distance with the parameters given.

I need to be able to define a specific amount of time that a move will last, and calculate what the peak velocity should be when all other factors are known. Starting velocity is not always zero, but ending velocity will always zero for my purposes. The move will always be trapezoidal.

I have an equation for defining the distance traveled when all other factors are known, but I need to isolate the peak velocity to one side of the equation and I am not sharp enough at this math to be able to solve for the peak velocity. Any help would be greatly appreciated.

Assuming:
d = total distance traveled
t = total time
AC = acceleration
DC = deceleration
Vi = initial velocity
Vs = slewing (peak) velocity
Vf = final velocity

I have this equation which I believe is correct. I need to isolate Vs to one side:

d = [(Vs+Vi)/2]*[(Vs-Vi)/AC] + [(Vs+Vf)/2]*[(Vf-Fs)/DC] + Vs*[t-((Vf-Vs)/DC)-((Vs-Vi)/AC)]

I hope that's clear enough to read... If not I attached a JPG of the equation written out by hand.
 

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Since Vs appears in two factors of both the first and third terms, that equation is quadratic in Vs. Multiply everything out, determine the coefficients of V_x^2 and V_s, and use the quadratic formula.
 
Thanks for that... I'll give it a try. Am I correct that the x in Vx^2 you mentioned is supposed to be an "s" ? It's been a long time since I've done this kind of math so if I'm not entirely sure I'll get this right... if anyone has some more specific tips I'd love to hear them.

Lars
 
I am having a lot of trouble factoring the equation once I get it in quadratic form, so I can isolate Vs. Can anyone help? If someone can solve this for Vs or give me more help getting started I'd really appreciate it.

Lars
 
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