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Tri-integral help

  1. Jun 6, 2006 #1
    [tex] \int \int\int z dx dy dz [/tex]

    where the intergral area is determined by these curves:

    y=0,z=0,x+y=2,2y+x=6

    and the cylinder: y^2+z^2=4
     
  2. jcsd
  3. Jun 6, 2006 #2

    TD

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    Homework Helper

    What have you attempted so far or what difficulties do you have?

    PS: since you sent me a PM about LaTeX, here's a hint.
    You can create a 'nice' triple integral, with less space in between. Click for the code.

    [tex]\iiint z dx dy dz [/tex]
     
    Last edited: Jun 6, 2006
  4. Jun 6, 2006 #3
    [tex] \int_{2}^{6} dx \int_{2}^{2-x} dy \int_ {-2}^{\sqrt {4-y^2}} zdz [/tex]
     
    Last edited: Jun 6, 2006
  5. Jun 6, 2006 #4

    TD

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    Perhaps you should clarify that a bit, what are the limits for x,y,z?
     
  6. Jun 6, 2006 #5
    x:2<<6
    y:2<<2-x
    z:-2<< sqrt(4-y^2)

    but i'm cofused about x,y limits, i'm not sure and i mix between those too many curves to get the variable limits
     
  7. Jun 12, 2006 #6
    I wonder why nobody hasen't reply on my post yet! Have I made a mistake or something wrong?
     
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