# Tri-integral help

1. Jun 6, 2006

### electronic engineer

$$\int \int\int z dx dy dz$$

where the intergral area is determined by these curves:

y=0,z=0,x+y=2,2y+x=6

and the cylinder: y^2+z^2=4

2. Jun 6, 2006

### TD

What have you attempted so far or what difficulties do you have?

PS: since you sent me a PM about LaTeX, here's a hint.
You can create a 'nice' triple integral, with less space in between. Click for the code.

$$\iiint z dx dy dz$$

Last edited: Jun 6, 2006
3. Jun 6, 2006

### electronic engineer

$$\int_{2}^{6} dx \int_{2}^{2-x} dy \int_ {-2}^{\sqrt {4-y^2}} zdz$$

Last edited: Jun 6, 2006
4. Jun 6, 2006

### TD

Perhaps you should clarify that a bit, what are the limits for x,y,z?

5. Jun 6, 2006

### electronic engineer

x:2<<6
y:2<<2-x
z:-2<< sqrt(4-y^2)

but i'm cofused about x,y limits, i'm not sure and i mix between those too many curves to get the variable limits

6. Jun 12, 2006

### electronic engineer

I wonder why nobody hasen't reply on my post yet! Have I made a mistake or something wrong?