Triangle and tangent line circle

jeajea
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A triangle ABC, where ,<A = 60 degrees. Let O be the inscribed circle of triangle ABC, as shown in the figure. Let D, E, and F be the points at which O is tangent to the sides AB, BC and CA. And let G be the point of intersection of the line segment AE and the circle O. (but AE line not cross point O as a center of circle). Set x=AD


1.Let ADF be the area of the triangle ADF.Then ADF/(AG.AE)= ?
2. When BD=4 and CF=2 then BC=? and x satified the equation X^2+Px-Q=0
Solving this equation, we have AD=R




I hope some one can help me i have tried it a lot of time but still can't solve it
 
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Have you drawn a diagram? Or attach that figure that's referred to in the question.

Also, could you show your attempts so far?

:smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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