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## Homework Statement

If I have a triangle that has the hypo as √(u^2 +1)

adj as 1 and oppo as u

I did an integral with trig sub. So I used

## Homework Equations

u = tan(θ)

## The Attempt at a Solution

At the end of my integral I ended up with an expression (1/4)sin(2θ)

When I substitute back in to the integral for theta. I will get (1/2)(u/(sqrt(u^2 +1))

right? How does back sub work if you have 2(theta)