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## Homework Statement

Find all angles x, -pi <= x <= pi which satisfy sin4x = 1

## Homework Equations

## The Attempt at a Solution

Solved x, ie

4x = sin^-1(1)

4x = pi/2

x = pi/8

Sine is positive for angles in quadrants one and two, so there's one other angle which is in quadrant two?

x = pi - pi/8

x = 7pi/8

Final answer, x = pi/8, 7pi/8

Just not feeling confident. There are about five other similar questions, ie solving x between -pi and pi