Trig Function Help: Get Answers Now

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    Function Trig
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The discussion centers around solving a trigonometric problem involving the double angle formula for cosine, specifically cos(2t). Participants clarify the need to find the value of t using cotangent and tangent relationships, with one user drawing a triangle to aid in calculations. The formula for cos(2t) is provided as cos²(t) - sin²(t), and there is a mention of the necessity to understand the process without a calculator for test purposes. Ultimately, the group converges on finding the correct values through reference triangles and trigonometric identities. The conversation emphasizes the importance of mastering these concepts for academic success.
Eric Manuel
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thanks
 
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Can you give the entire problem?
 
Jimmy Johnson said:
Can you give the entire problem?

all that's given is that
 
What is the question? What are you asked to find?
 
MostlyHarmless said:
What is the question? What are you asked to find?
what is =cos2x
 
What is x supposed to be? Is the given problem in terms of t? Are you trying to solve for t and then plug that value in for x?
 
oh my bad its cos2t

its basically asking you to use the double angle formula
but I am not sure how to find those values
 
If you're simply trying to find t, then use cot = 1/tan... If you have a value for t why do you need to use the double angle identities?
 
to find what cos2t is ...

you can find what tan is from cot
then i drew a triangle and got the hypot to be sqrt(41)

but how do i do that math

formula for cos2t = cos^2(t) - sin^2(t)
 
  • #10
Are you forbidden from using a calculator?
 
  • #11
Jimmy Johnson said:
Are you forbidden from using a calculator?

teacher said u can use it
but need to know how to do it without one for test
 
  • #12
Well that may have been useful information at the start...

you have cot = -5/4, find what tan is then recall tan = sin/cos ... or recall cot = cos/sin...
 
  • #13
well i worked it out and i believe i got the answer to be 9/41
 
  • #14
That's what I'm getting
 
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