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Hi, I'm confused about using trig identities.

Match the trigonometric function with one of the following: (a) -1, (b) cos(x), (c) cotx (d) 1, (e) -tan(x), (f) sin(x)

(1-cos^2x)(cscx)

None that I know of.

I multiply it through, which gives me:

csc(x) - cos^2(x)(cscx)

I divide out csc(x) which gives me:

csc(x)(1 - cos^2(x)(1))

(got me nowhere really)

edit: I just realized that I can do

1-cos^2(x)=sin^2(x)

edit2: am I wrong in thinking that since cosecant is the reciprocal of sine, that in csc(sin^2x) one sine cancels out, leaving me with sin(x)?

I might of just solved my own problem :P can anybody confirm? Thanks

## Homework Statement

Match the trigonometric function with one of the following: (a) -1, (b) cos(x), (c) cotx (d) 1, (e) -tan(x), (f) sin(x)

(1-cos^2x)(cscx)

## Homework Equations

None that I know of.

## The Attempt at a Solution

I multiply it through, which gives me:

csc(x) - cos^2(x)(cscx)

I divide out csc(x) which gives me:

csc(x)(1 - cos^2(x)(1))

(got me nowhere really)

edit: I just realized that I can do

1-cos^2(x)=sin^2(x)

edit2: am I wrong in thinking that since cosecant is the reciprocal of sine, that in csc(sin^2x) one sine cancels out, leaving me with sin(x)?

I might of just solved my own problem :P can anybody confirm? Thanks

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