- #1

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## Homework Statement

cos+sintan/sinsec=csc

## Homework Equations

## The Attempt at a Solution

(cos+sin(sin/cos))/(sin/1/cos)

(cos+sin^2sincos)/(sin/cos)

(cos+sin^2sincos)X(cos/sin)

- Thread starter fouracres
- Start date

- #1

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cos+sintan/sinsec=csc

(cos+sin(sin/cos))/(sin/1/cos)

(cos+sin^2sincos)/(sin/cos)

(cos+sin^2sincos)X(cos/sin)

- #2

- 590

- 0

(cos+sin(sin/cos))/(sin/1/cos) to

(cos+sin^2sincos)/(sin/cos) ?

The cosine should become the LCM in the numerator.

- #3

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- #4

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where were u saying cos shud become the LCM in the numerator?

- #5

Mark44

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Have you ever heard of punctuation? The quote above appears to be three different sentences. Using periods at the ends of your sentences would make what you say easier to understand.

A similar problem exists with your first post (in addition to the omission of arguments of the functions shown):

As you have written it, most people in this forum would interpret the above as:cos+sintan/sinsec=csc

[tex]cos(x) + \frac{sin(x)tan(x)}{sin(x)sec(x)} = csc(x)[/tex]

I suspect that what you really meant, though, was this:

[tex]\frac{cos(x) +sin(x)tan(x)}{sin(x)sec(x)} = csc(x)[/tex]

If you don't know how to use LaTeX, you can write the equation above like so:

(cos(x) +sin(x)tan(x))/(sin(x)sec(x))=csc(x)

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