# Trig identities

## Homework Statement

cos+sintan/sinsec=csc

## The Attempt at a Solution

(cos+sin(sin/cos))/(sin/1/cos)
(cos+sin^2sincos)/(sin/cos)
(cos+sin^2sincos)X(cos/sin)

Related Precalculus Mathematics Homework Help News on Phys.org
How did you go from
(cos+sin(sin/cos))/(sin/1/cos) to
(cos+sin^2sincos)/(sin/cos) ?

The cosine should become the LCM in the numerator.

i think i multiplied sin by sin and cos i wouldnt doubt that i did it wrong can u correct me i really would love to fix this !!!

where were u saying cos shud become the LCM in the numerator?

Mark44
Mentor
i think i multiplied sin by sin and cos i wouldnt doubt that i did it wrong can u correct me i really would love to fix this !!!
Have you ever heard of punctuation? The quote above appears to be three different sentences. Using periods at the ends of your sentences would make what you say easier to understand.

A similar problem exists with your first post (in addition to the omission of arguments of the functions shown):
cos+sintan/sinsec=csc
As you have written it, most people in this forum would interpret the above as:
$$cos(x) + \frac{sin(x)tan(x)}{sin(x)sec(x)} = csc(x)$$

$$\frac{cos(x) +sin(x)tan(x)}{sin(x)sec(x)} = csc(x)$$