- #1

StarkyDee

Law of sines:::

i cant figure out how to use new latex for this ........

sin a / a = sin b / b = sin c / c

thanks

- Thread starter StarkyDee
- Start date

- #1

StarkyDee

Law of sines:::

i cant figure out how to use new latex for this ........

sin a / a = sin b / b = sin c / c

thanks

- #2

ShawnD

Science Advisor

- 668

- 1

A diagram of what you mean would really really help.

- #3

- 72

- 0

Okay, call the height of the tower 'a' and the distance along the ground toward the tower 'c'. You need to think of a right-angled triangle with base 'c' and opposite leg 'a'.

When the boys take their measurements from the second-floor window, think of a different triangle, this one with opposite side (a - 24)ft in height. You may notice that the base 'c' does not change between these two locations.

Therefore

a/(sin 52) = c/(sin (90 - 52)) = c/(sin 38)

and

(a - 24)/(sin 44) = c/(sin(90 - 44)) = c/(sin 46)

Since

a/(sin 52) = c/(sin 38)

a = c(sin 52)/(sin 38)

And also, since

(a - 24)/(sin 44) = c/(sin 46)

a = c(sin 44)/(sin 46) + 24

So, now we know that

c(sin 44)/(sin 46) + 24 = c(sin 52)/(sin 38)

And that

c = 24/[(sin 52)/(sin 38) - (sin 44)/(sin 46)]

From before, we found that

a = c(sin 52)/(sin 38)

So substitute your value for c into this equation and that will yield your answer.

- #4

StarkyDee

i think i have the first triangle right..but where does the 2nd one go?

- #5

- 72

- 0

- #6

- 72

- 0

Did you get the e-mail, Starky? Or did it not go through?

- #7

StarkyDee

sincerely,

~david

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