Trig substitition-lost in identities

  • Thread starter Thread starter phantomcow2
  • Start date Start date
  • Tags Tags
    identities Trig
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 1K views
phantomcow2
Messages
52
Reaction score
0
Trig substitition--lost in identities

Homework Statement



[tex]\int[/tex][tex]\frac{dx}{x^{2}\sqrt{x^{2}+1}}[/tex]

Homework Equations


It's pretty obvious that this is a trig substitution problem requiring use of tangent.


The Attempt at a Solution



[tex]x=tan\theta[/tex]
[tex]dx=sec^{2}\theta[/tex]
[tex]x^{2}=tan^{2}\theta[/tex]

Substitute it in.

[tex]\frac{sec^{2}\theta}{tan^{2}\theta\sqrt{tan^{2}\theta + 1}}[/tex]

But the [tex]\sqrt{tan^{2}\theta + 1}[/tex] simplifies to [tex]sec\theta[/tex]

Now before I integrate, I need to simplify. The obvious simplification is the [tex]sec^{2}\theta[/tex] and [tex]sec\theta[/tex] in the denominator, leaving me with
[tex]\frac{sec\theta}{tan^{2}\theta}[/tex]

This is starting to look fishy to me. I think I've begun to develop an instinct telling me when I am doing something incorrectly. I simplify this to [tex]\frac{cos\theta}{sin^{2}\theta}[/tex]

Now I need to ingrate this, but it doesn't look promising. Can someone tell me where I went wrong?
 
Physics news on Phys.org


Oh, haha, you're right! I need to start thinking to substitute more often :p

u= sin and du = cos

Yep, straight forward from here. Thanks so much.