Trig substitition-lost in identities

  • Thread starter Thread starter phantomcow2
  • Start date Start date
  • Tags Tags
    identities Trig
Click For Summary
SUMMARY

The discussion focuses on solving the integral \(\int\frac{dx}{x^{2}\sqrt{x^{2}+1}}\) using trigonometric substitution. The user correctly identifies the substitution \(x = \tan\theta\) and simplifies the expression to \(\frac{\sec\theta}{\tan^{2}\theta}\). However, confusion arises during the integration process, leading to a further substitution of \(u = \sin\theta\) and \(du = \cos\theta\) to facilitate the integration. The conversation highlights the importance of recognizing when to apply substitutions in trigonometric integrals.

PREREQUISITES
  • Understanding of trigonometric identities and functions
  • Familiarity with integration techniques, particularly trigonometric substitution
  • Knowledge of calculus, specifically integral calculus
  • Ability to manipulate algebraic expressions involving trigonometric functions
NEXT STEPS
  • Study advanced trigonometric substitution techniques in calculus
  • Learn about the properties and applications of trigonometric identities
  • Practice integrating complex rational functions using substitution methods
  • Explore the use of \(u\)-substitution in various integral problems
USEFUL FOR

Students and educators in calculus, particularly those focusing on integration techniques, as well as anyone seeking to improve their skills in solving trigonometric integrals.

phantomcow2
Messages
52
Reaction score
0
Trig substitition--lost in identities

Homework Statement



\int\frac{dx}{x^{2}\sqrt{x^{2}+1}}

Homework Equations


It's pretty obvious that this is a trig substitution problem requiring use of tangent.


The Attempt at a Solution



x=tan\theta
dx=sec^{2}\theta
x^{2}=tan^{2}\theta

Substitute it in.

\frac{sec^{2}\theta}{tan^{2}\theta\sqrt{tan^{2}\theta + 1}}

But the \sqrt{tan^{2}\theta + 1} simplifies to sec\theta

Now before I integrate, I need to simplify. The obvious simplification is the sec^{2}\theta and sec\theta in the denominator, leaving me with
\frac{sec\theta}{tan^{2}\theta}

This is starting to look fishy to me. I think I've begun to develop an instinct telling me when I am doing something incorrectly. I simplify this to \frac{cos\theta}{sin^{2}\theta}

Now I need to ingrate this, but it doesn't look promising. Can someone tell me where I went wrong?
 
Physics news on Phys.org


Nothing wrong so far. Time for another substitution.
 


Oh, haha, you're right! I need to start thinking to substitute more often :p

u= sin and du = cos

Yep, straight forward from here. Thanks so much.
 

Similar threads

Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
28
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K
  • · Replies 34 ·
2
Replies
34
Views
6K
Replies
7
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K