- #1
nightshade123
- 82
- 0
Homework Statement
[tex]\int[/tex] ((sin(x))^3/(cos(x)) )*dx
The Attempt at a Solution
alright i have been trying to use
u= cosx
-du = sinx
but it doesn't make sense bause there is still a sinx^2 to account for
so i know i need to make a trig substitution but i can't figure out the appropriate
substitution for sinx^2 even though i think the 1/2 ( 1- cos2x) is hte only one question... when u use a u substituion for u = cosx -du = sindx would u write
1/2 [tex]\int[/tex] ((sinx*( 1 - cos2x)) / cosx)*dx- 1/2 [tex]\int[/tex]( (1 - 2u) / u ) *du
if u = cosx and u have to change a cos2x... what would you write 2u... that wouldn't make sensebecause it would come out 2*cosx which does not equatl cos2x
idk where I am lost... i can't logically follow through this problem for some reason, any advice would be amazing, thanks for your time.
Last edited: