Trig Substitutions Homework: "Uh... why?

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The discussion revolves around understanding the steps in a trigonometric substitution problem, specifically focusing on the derivative of the sine function. Participants express confusion about why the derivative of sine is cosine, particularly in the context of the given substitutions and equations. There is a clarification that the relationship between x and sin(θ) must be properly established, emphasizing the need for correct notation. The conversation highlights the importance of grasping the fundamental principles of trigonometric derivatives in solving these types of problems. Overall, the thread seeks to clarify the reasoning behind the derivative in the context of trigonometric substitutions.
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Homework Statement


This is only a step in a bigger example problem on trig substitution
2/3 *x2 = sin2\theta
\sqrt{}2/3 * x =sin\theta
\theta = arcsin(\sqrt{}2/3 * x)
and
x = \sqrt{}3/2 * sin\theta
This makes sense
Then I saw
dx / d\theta = \sqrt{}3/2 * cos\theta
Uh... why?

Homework Equations


Regular trig equations


The Attempt at a Solution


I have no idea
 
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What exactly is your question? Why is the derivative of sine, cosine?
 
Sourabh N said:
What exactly is your question? Why is the derivative of sine, cosine?

Yeah
 
nhmllr said:

Homework Statement


This is only a step in a bigger example problem on trig substitution
2/3 *x2 = sin2\theta
\sqrt{}2/3 * x =sin\theta
You can't conclude what you have above. This is what it should be.
\sqrt{2/3} * x = \pm sin (\theta)

nhmllr said:
\theta = arcsin(\sqrt{}2/3 * x)
and
x = \sqrt{}3/2 * sin\theta
This makes sense
Then I saw
dx / d\theta = \sqrt{}3/2 * cos\theta
Uh... why?

Homework Equations


Regular trig equations


The Attempt at a Solution


I have no idea
 
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