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To simplify expressions like cos(sin-1(x)), one can use the relationship between sine and cosine in a right triangle. By defining an angle θ where sin(θ) = x, it follows that cos(θ) can be derived from the Pythagorean identity, leading to cos(sin-1(x)) = √(1 - x²). Similarly, for other inverse functions, analogous relationships can be established, such as sin(cos-1(x)) = √(1 - x²) and tan(cot-1(x)) = 1/x. These simplifications rely on the properties of right triangles and the definitions of the inverse trigonometric functions. Understanding these relationships allows for the reduction of complex expressions involving arc functions.
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Is there any way I can reduce or simplify expressions like cos(sin-1(x)), sin(cos-1(x)), cos(tan-1(x)), tan(cot-1(x)) etc.? (I refer to the arc functions, i.e. inverses, by the superscript -1, not the reciprocals)
 
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Hint: sin(sin-1(x)) = x and cos(w) = sin(w+π/2).
 
You can use this relation:
ArcSin((1-x^2)^0.5)=ArcCos(x)
 
Astudious said:
Is there any way I can reduce or simplify expressions like cos(sin-1(x))

Draw a right triangle with an angle \theta, opposite side length of x and hypotenuse length 1. Now from this triangle, by definition,

\sin\theta = x
hence
\theta = \sin^{-1}x

So then what is \cos\left(\sin^{-1}x\right), or more simply, \cos\theta ?
 
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