Trigonometric Formulas, Identities and Equation

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Homework Help Overview

The discussion revolves around finding sin 2t given that cos t = 4/5, within the context of trigonometric formulas and identities.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses confusion about how to start the problem and seeks guidance on the first steps. Some participants suggest finding sin t using the given cos t value and refer to double-angle formulas.

Discussion Status

Participants are exploring different approaches to the problem, with some providing hints about using trigonometric identities. There is an indication that the original poster has gained some understanding but is still seeking further assistance.

Contextual Notes

The original poster mentions feeling overwhelmed and requests help, indicating a need for clarification on the problem setup and the application of trigonometric identities.

palui123
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Homework Statement


t = tetha

FInd sin 2t when cos t = 4/5

Homework Equations



no idea

The Attempt at a Solution



no. . . . btw what should I do 1st? I don't understand this question
 
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1) You are given that cos t = 4/5. Can you find sin t?
2) Do you know your trig identities? Particularly the double-angle formulas.
 
palui123 said:

Homework Statement


t = tetha

FInd sin 2t when cos t = 4/5

Homework Equations



no idea

The Attempt at a Solution



no. . . . btw what should I do 1st? I don't understand this question
Exactly what part of "Find sin 2t" do you not understand?
 
Formula:
Sin2t = 2 sint costWhat I do is:
Sin2t = 2sint cost

since cost = 4/5

sin2t = 2sint (4/5)

sin2t = 8sint/5

What should I do then..? I know its wrong
 
w8. . . nvm. I know how to this question now.

sin 2t = 2 sint cost

since cost = 4/5 ,

a=4 , h=5 , o=??

P.theorem:
a^2=b^2+c^2
o=3

then sint = 3/5

then subtitude =D . . . solve get the answer. . .I'm talking by myself T-T ask = me , answer = me T-T . AID ME NEXT TIME PLEASE. . . .
 
palui123 said:
I'm talking by myself T-T ask = me , answer = me T-T . AID ME NEXT TIME PLEASE. . . .
If by "aiding you" you mean, show you the work + answer, then NO, WE CAN'T DO THAT. Read the forum rules. Otherwise, I think I gave you sufficient aid in my post (#2).
 

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