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## Homework Statement

Evaluate the definite integral of function

**dx/x^2+1**on interval

**[tan(3), tan(6)]**

## Homework Equations

## The Attempt at a Solution

The trigonometric inverse function for dx/x^2+1 is arctanx+c.

I plugged in tan(3) and tan(6), and subtracted arctan(tan(3)) from arctan(tan(6)) and got the answer -.1415. But it's incorrect...

What am I doing wrong?