TRIGONOMETRY equation derivation [HELP]

hgphtgi
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The signal length from satellite to the Earth station (AC) can be found as


2(H)/[{sin^2(theta)+(2(H)/R)}^1/2+sin(theta)] Due to the Earth projection

where "H" is satellite height and and R is the Earth radius

My question is Can you help me to derive this equation? how they have obtained it?

Regards
 

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??

that's the wrong diagram :confused:
 
tiny-tim said:
??

that's the wrong diagram :confused:

No tiny, that is what i mean :) this is my question
 
hgphtgi said:
The signal length from satellite to the Earth station (AC) can be found as2(H)/[{sin^2(theta)+(2(H)/R)}^1/2+sin(theta)] Due to the Earth projection

where "H" is satellite height and and R is the Earth radius

My question is Can you help me to derive this equation? how they have obtained it?

Regards

What is theta in the diagram? I don't see it. Also, I'm assuming that ##\stackrel{\frown}{AC}## doesn't contain B, correct?

You aren't being very specific. If you want our help, give us the necessary information. :confused:

I'm thinking your equation is ##||\stackrel{\frown}{AC}||=\frac{2h}{\sqrt{\sin^2\theta+\frac{2h}{r}}+\sin(\theta)}##.

Edit:
Preliminarily (I don't know what theta is in the diagram), I'm thinking the rough outline of a proof might be along the lines of this:

1. Consider O (the center of earth) as the center of a coordinate system.
2. Defining points A, B, and C in terms of the Earth as a circle (set of all points equidistant from O)
3. Noting that arc AC is on a circle centered at some new point ##(x_1,y_1)## with radius ##\sqrt{x^2+(r+h-y_1)^2}##.
4. ##s=r\theta##
 
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