Trigonometry Identities: Simplifying Higher Powers

NotAMathWhiz
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1. sec^4 x + sec^2 x tan^2 x - 2 tan^4 x = ?
The possible answers are:
a. 4 sec^2 x
b. 3 sec^2 x - 2
c. sec^2 x + 2
d. tan^2 x - 1



Homework Equations



No idea.

The Attempt at a Solution



I'm not sure where to begin here. My book first doesn't cover anything above squared, and when it does, the equation is by itself and immediately shows an easy way to convert to simpler terms. I'm confused however on how to convert this equation.

does sec^4 x = 1/cos^4 x?
 
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Yes, sec^4 x is 1/cos^4 x. Try converting everything in the expression to sines and cosines.
 
okay, so is this correct?

1/cos^4 x + 1/cos^2 x * sin^2 x/cos^2 x - 2(sin^4 x/cos^4 x)
 
Yes. Now factorize out \frac 1{cos^4x} and factorize the terms containing sin^2x. Now, you should be able to apply well known identities to get a numerator that only contains terms involving cos^2x. Now, it should be clear what the answer is.
 
Yes, now simplify that.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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