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Trigonometry problem

  1. Oct 12, 2004 #1
    find the angle x
    if its known that:
    sin(x/2) = 1/2
    tan(x)=sqrt(3)

    0<=x<=360
     
  2. jcsd
  3. Oct 12, 2004 #2

    Pyrrhus

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    why don't you simply do arcsine and arctan?
     
  4. Oct 12, 2004 #3
    because the whole point of the question is using trigonometric identities to solve it (believe me i would be happy to do the arctan and get it over with :smile: )
     
  5. Oct 12, 2004 #4

    NateTG

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    You might discover something interesting about the problem though. (It's also worth noting that that there are special angles involved.)
     
  6. Oct 12, 2004 #5
    i tried playing around with it

    sin(x/2) = 1/2
    tan(x)=sqrt(3)

    i got

    tan(x) = sin(x) / cos(x) = sqrt(3)

    sin^2(x) / cos^2(x) = 3

    but that didn't really lead me anywhere
    i thought of ways to convert sin(x/2) to sin(x) with no luck
     
  7. Oct 12, 2004 #6

    Tide

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    If you don't want to use the inverse trig functions directly then you may want to ponder the equilateral triangle!
     
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