Hmm...what is the coefficient of friction between the tires and the incline?
Assuming the ramp is frictionless, your "force" must contain a component parallel to the ramp, with magnitude:
F = \left( {2000 \, {\text{lb}}} \right)\sin \frac{\pi }{6} = 1000\,{\text{lb}}
Basically, gravity will exert
1000 lb down the ramp. To keep the car from rolling down, you must exert a force of
1000 lb UP the ramp (parallel to the ramp, antiparallel to the component of weight parallel to the ramp).
However, if you
do have friction, then to prevent
rolling down the ramp (NOT skidding!), you must find the coefficient of 'static' friction between the tires and the ramp. Now, let \mu _S represent this value. Thus, the force needed to prevent the car from rolling down is:
F = 2000\,{\text{lb}}\left( {\sin \frac{\pi }{6} - \mu _S \cos \frac{\pi }{6}} \right) = 1000\,{\text{lb}}\left( {1 - \mu _S \sqrt 3 } \right)
**In the direction antiparallel to the weight component parallel to the ramp.
Well the basic idea is good but I don't know how you came up with cos. If you look at a scetch you should be abel to find the right function for the force perralel to the slope. And just a small hint when your searching for a force it's usually a good idea to use weight instead of mass (I'm not very good at non-metric units soo I don't really know wheater lb steands for mass or weight).
What basic idea? Also, by "sketch", do you mean a free-body diagram?
Anyway, those are always helpful (Unless you're in a pinch for time!...or the problem is just basic).
Also "lb" stands for pounds, which are a customary unit of
weight, I believe, according to
http://dictionary.reference.com/search?q=lb
http://dictionary.reference.com/search?q=pound
