Triple Integral: Volume Between Y=1-X & Y=Z^2-1

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Homework Statement


Volume between Y=1-X and Y = Z^2 -1

The Attempt at a Solution



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Sorry, not a good drawer.

0 < y < 1
0< x < SqRoot: 1-y

-1 < y < 0
0 < Z < Sqroot: 1 + y

I'm not even sure if this is right, we just started the triple integrals. Please Help.
 
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The problem is that the plane y= 1- x and the parbolic cylinder [math]y= z^2- 1[/math] are not boundaries for a bounded region.
 
So there is not enough information?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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