Trivial Eigenspace: Definition & Meaning

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Homework Help Overview

The discussion revolves around the concept of "trivial eigenspace" within the context of linear transformations and eigenspaces in vector spaces. Participants are exploring definitions and implications related to eigenvectors and eigenvalues, particularly focusing on the zero vector and its role in eigenspaces.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to clarify the meaning of "non-trivial" in relation to eigenspaces, questioning the definition of eigenvectors, particularly the exclusion of the zero vector. There is also discussion about the implications of diagonalizability and the relationship between minimal and characteristic polynomials.

Discussion Status

The discussion is active, with participants sharing insights and interpretations. Some guidance has been offered regarding the algebraic closure of fields and the use of Jordan forms, though there is no explicit consensus on the definitions or the relationships being explored.

Contextual Notes

Participants are navigating the definitions of eigenvectors and eigenspaces, particularly the status of the zero vector. There is mention of the dimensionality of eigenspaces and the conditions under which certain properties hold, such as diagonalizability.

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What's a "trivial eigenspace"?
 
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Put it in context. Probably something to do with 0, and probably 0 as a vector.
 
"Let V be a vector space of dimension n over a field F, and let T:V->V be linear. Let R={linear transformations V->V that commute with T}.

Suppose T is diagonalisable, show that T is a commutative ring <=> all non-trivial eigenspaces of T are one-dimensional."

I just need to know what "non-trivial" means in this case. We defined the 0 vector to NOT be an eigenvector.
 
0 is not en eigenVECTOR, agreed, but as a subvector space 0 is an eigenSPACE, the trivial eigenspace.
 
How do I show that R is commutative <=> the minimal and characteristic polynomials of T are the same? (T might not be diagonalizable)
 
does that mean you've done the first question?

There is no harm in passing to the algebraic closure of your field if it helps you to think about it. Put everythin in jordan form, what can you say about the commuting matrices? just to give you some idea of how to use the difference between the minimal and characeristic poly.
 
Yes, I did the first question. I've got an idea about the second one that doesn't involve Jordan forms, but I'm still working on it.
 

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