Trouble Solving a Ladder Problem: Need Help!

  • Thread starter Thread starter naeblis
  • Start date Start date
AI Thread Summary
The discussion focuses on solving a physics problem involving a uniform ladder resting against a frictionless wall, with a static friction coefficient of 0.3. The original poster is struggling to connect the concepts of static friction and forces acting on the ladder, including the normal force and weight. They have established some equations related to static friction and force balance but are unsure how to incorporate torque into their analysis. A key point emphasized is the importance of ensuring that the sum of torques about any point also equals zero for the ladder to remain stationary. The conversation highlights the need for a clearer understanding of the relationship between these forces and torques in solving the problem.
naeblis
Messages
26
Reaction score
0
hey I've been trying this problem and any way i try i always seem to not have enough info i think I am missing a keyconcept to help get more info outa the problem, well ne way here is the question

Q: A uniform ladder rests against a frictionless vertical wall. the coefficient of static friction = 0.3. what isthe smallest angle at which the ladder will remain stationary?

alli have comeup with is that fs / Fn = .3 and that summation Fx = 0 = fs -F1 ;fs = F1 and Fn-w = 0 so Fn = weight

im not really sure how any of this relates to the other stuff, hopefully some one can help me out on this.

thanx in advance.
 
Physics news on Phys.org
Don't forget that the torques about any point must also sum to zero.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top