Trouble solving an ordinary differential equation

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Homework Help Overview

The discussion revolves around solving an ordinary differential equation (ODE) of the form \(\frac{d M}{dt}=k_1M-k_2(1-M)=A\exp \left (-\frac{E}{T} \right )M-B\exp \left ( -\frac{F}{T} \right )(1-M)\). Participants are exploring methods to find a solution and clarifying the structure of the equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for a correct integration approach, with one noting the importance of recognizing that \(M\) is a function of \(t\). There is mention of making the equation separable through substitution. Others provide examples of separable ODEs and suggest using integrating factors as a standard method for nonhomogeneous first-order ODEs.

Discussion Status

The discussion is active, with participants offering various methods to approach the problem, including suggestions for substitutions and integration techniques. There is no explicit consensus on a single method, but multiple strategies are being explored.

Contextual Notes

Participants are working under the constraints of the original problem statement and are questioning the correctness of the initial integration attempt. There is also a mention of a potential typo in the proposed solution, indicating uncertainty in the formulation.

Hypatio
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Homework Statement



Find the appropriate equation.

Homework Equations



So there we have the ordrinary differential equation

[itex]\frac{d M}{dt}=k_1M-k_2(1-M)=A\exp \left (-\frac{E}{T} \right )M-B\exp \left ( -\frac{F}{T} \right )(1-M)[/itex]

The goal is to solve the differential equation. It turns out the solution should be something like this:

[itex]M=\frac{k_2}{K_1+k_2}+\frac{k_1}{K_1+k_2}\exp -(k_1+k_2)t[/itex]

although I think there may be a typo around the last exp (im not sure if t is inside the exponent or not)


The Attempt at a Solution



After integrating over t I get

[itex]M=Mt(k_1+k_2)-k_2 t[/itex]

But I'm not even sure this is the correct integral of the equation as I don't know how the supposed solution follows from this.
 
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You integration over t is not correct, you need to remember M=M(t) is a function of t.

To integrate directly the DE must be separable, this one is not but i think it can be made so with a simple substitution
 
An example of a separable DE is as follows
[tex] \frac{dx}{dt} = kx[/tex]

rearranging and integrating gives
[tex] \int\frac{dx}{x} = k\int dt[/tex]
[tex] ln(x) = kt+c[/tex]
[tex] x = e^{c}e^{kt}[/tex]
 
or write your ODE as
M' = aM+b

and make the subsitution
N = aM+b
 

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