Engineering Troubles with a circuit analysis situation (RLC circuit)

AI Thread Summary
The discussion focuses on analyzing an RLC circuit, specifically the voltage across a 2 Ω resistor at time t = 0+. At t = 0-, no current flows due to the steady state of the circuit, resulting in zero voltage across the resistor. Participants confirm that the initial voltage across the capacitor is -20 volts, calculated using Kirchhoff's Voltage Law (KVL). The conversation emphasizes that the capacitor's potential difference must satisfy KVL, reinforcing the concept that the inductor's voltage remains zero when current is unchanged. Understanding these principles is crucial for accurate circuit analysis.
Anti Hydrogen
Messages
37
Reaction score
4
Homework Statement
the book doesn't explain how they calculated the initial value of the voltage of the 2 ohms resistance and the inductor current; i understand, however, how they calculated the initial value of the capacitor. i think they are taking the voltage of the open circuit in left as zero so that the voltage of resistance takes the value of zero too; if so, why is the open circuit voltage zero?, the definition of open circuit according to the book says that voltage of a open circuit can be any value. note that the open circuit in the left of the circuit comes from a singularity funtion
Relevant Equations
please any help will be appreciated!
thanks
 

Attachments

  • Untitled.png
    Untitled.png
    21 KB · Views: 272
Physics news on Phys.org
Hi Anti Hydrogen,

It's not entirely clear to me what you're asking. Is it for the voltage across the 2 Ω resistor at time t = 0+ ?
 
gneill said:
Hi Anti Hydrogen,

It's not entirely clear to me what you're asking. Is it for the voltage across the 2 Ω resistor at time t = 0+ ?
it is at t=0 minus
 
gneill said:
Hi Anti Hydrogen,

It's not entirely clear to me what you're asking. Is it for the voltage across the 2 Ω resistor at time t = 0+ ?
it is the initial value, this is, at t less than 0
 
Okay. Well, at t= 0- there's no current being supplied by the current source, and no current due to the voltage source either (at steady state the capacitor looks like an open circuit). So, no current flowing anywhere. What does that tell you about the current through that resistor?
 
  • Skeptical
Likes Anti Hydrogen
it's zero too, hence, the voltage across it is zero?
 
Anti Hydrogen said:
it's zero too, hence, the voltage across it is zero?
Yup.
 
  • Like
Likes Anti Hydrogen
.
gneill said:
Yup.
i calculated the voltage across the right open circuit applying the KVL in right mesh,
-20-vc=0
then
vc=-20
im i right?
 

Attachments

  • Untitle8d.png
    Untitle8d.png
    2.8 KB · Views: 225
Yes. At steady state the capacitor must have a potential difference that satisfies the KVL around the loop, but more obviously, since there's no current change through the inductor the potential at the top of the inductor with respect to the bottom of the inductor must be zero. Hence the sum of the voltage source and capacitor voltage must be zero.
 
  • Like
Likes Anti Hydrogen

Similar threads

Replies
5
Views
3K
Replies
8
Views
2K
Replies
9
Views
11K
Replies
3
Views
2K
Replies
4
Views
1K
Replies
13
Views
7K
Replies
4
Views
2K
Back
Top