Troubleshooting Kepler's Third Law with Halley's Comet

AI Thread Summary
The discussion revolves around troubleshooting Kepler's Third Law using Halley's Comet, where a user calculates a semimajor axis of 38.56 AU instead of the expected 17 AU. Key parameters include the period of Halley's Comet (76 years), the mass of the Sun, and gravitational constant G. It is noted that the result is affected by a potential error in the calculations, particularly regarding the proportionality constant when using astronomical units and years. Participants emphasize the importance of accuracy in these calculations and share experiences of common errors in astrophysics. The conversation highlights the challenges of numerical precision in astronomical computations.
ehrenfest
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Homework Statement


When I plug in all of the parameters for Halley's comet (from Wikipedia) into Kepler's third law a get a semimajor axis of 38.56 AU when it should be about 17? Can someone else try it and see if I am crazy?

Homework Equations


The Attempt at a Solution

 
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What parameters are you trying to plug into what equation?
 
mass of halley's comet = negligable
mass of the sun
G
T = 76 years
 
I get that 76^2 is pretty close to 17.8^3. Perhaps you are crazy. :) Remember that the Earth semimajor axis is 1 AU and it's period is 1 year.
 
OK here are the details:

38.5654 = (T^2/(4 pi^2) * G * (Ms))^(1/3)/(1.4*10^11)

where T is the period in seconds, Ms = 1.991*10^31 and G = 6.674 * 10^(-11)
what am I doing wrong?
 
ehrenfest said:
OK here are the details:

38.5654 = (T^2/(4 pi^2) * G * (Ms))^(1/3)/(1.4*10^11)

where T is the period in seconds, Ms = 1.991*10^31 and G = 6.674 * 10^(-11)
what am I doing wrong?

The mass of the Sun is 1.99*10^30 kg... (Your result for a is off by very nearly the cube root of 10.)
 
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You beat me! I just figured that out. But, ehrenfest, for solar orbits if you work in AU and years, the constant proportionality k in R^3=k*T^2, is one.
 
Dick said:
You beat me! I just figured that out. But, ehrenfest, for solar orbits if you work in AU and years, the constant proportionality k in R^3=k*T^2, is one.

My training's largely in astrophysics, so I have the solar mass by heart. I would usually take the proportionality approach myself as well, though...
 
Funny, my training is in cosmology, so I know it's like to ten the fifty some proton masses. And fifty plus what I forget. Good job.
 
  • #10
Ahh! 30 minutes of frustration because my short-term memory is not good enough to look at a computer screen and then write down a two-digit number without botching a digit!

Thanks guys.
 
  • #11
Dick said:
Funny, my training is in cosmology, so I know it's like to ten the fifty some proton masses. And fifty plus what I forget. Good job.

Close enough... ;-) When I was an undergraduate, cosmology was called "the science where you're happy when your order of magnitude is right to an order of magnitude". Nowadays we speak of "precision" cosmology -- what an age we live in...
 
  • #12
ehrenfest said:
30 minutes of frustration...

Everybody makes copying errors (when they're not making *sign* errors), so I know just how you feel...
 
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