Troubleshooting Leaking Water: Expert Tips to Solve the Problem

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I'm stuck please help me... thanks
 
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Didn't they also give you the water level in the tank? I think you need that as well.
 
no, they didn't :(
 
It isn't labelled in a diagram or anything? Their mistake, I think. Then suppose the water level of the tank is L above the vertex (you can plug in the number for L later). Can you express the rate in terms of L?
 
v=1/3 pi r^2h

substitute r= 3h/2

V= (3pi h^3)/4

d/dt ( V = (3pi h^3) / 4 )

R= (27pi/8)h^2 + 0.5

is this right?
 
Looks fine to me.
 

Thread 'Prove that the integral is equal to ##\pi^2/8##'

Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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