Calculating Velocity and Acceleration of a Truck in Motion

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A truck traveling east has an initial velocity of 26 m/s and accelerates at 1 m/s², resulting in a velocity of 27 m/s after one second. It then decelerates at -2 m/s² for 3 seconds, leading to a final velocity of 21 m/s. A discussion arose about a potential typo in the problem, as the final acceleration for part (c) seemed unclear when the truck reached 21 m/s after 8 seconds. Clarification on the acceleration duration was needed, with suggestions to consider different acceleration values. The conversation emphasized the importance of correctly interpreting the problem's parameters for accurate calculations.
Rylynn97
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A truck traveling east has a velocity of 26 m/s. (a) Calculate its velocity after accelerating at 1 m/s2. (b) The truck then decelerates at -2 m/s2 for 3 s. Now what is its velocity? (c) The truck then takes 8s to change its velocity to 21 m/s. What was its final acceleration?

I tried using 1s (a), and I got 27 m/s. Using 27 m/s in (b), I got 21 m/s. But then for (c) the velocity is also 21, so it doesn't make any sense. Help?
 
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The process you followed is exactly right. I would guess that there's some typo in the problem. But for part C, if the truck was at 21 m/s then took 8s to get to 21 m/s. What would it's acceleration be?
 
Ahh, I see. Thank you! ^___^
 
just a little discussion, In part (a), how about the car accelerating at 3 m/s2, then the answer will be 29m/s2 ?
 
willingtolearn said:
just a little discussion, In part (a), how about the car accelerating at 3 m/s2, then the answer will be 29m/s2 ?

In part a) is it accelerating for 1s ? doesn't say in the question, but I'm guessing it's supposed to be...

Yeah, then it would come out to: v = v0 + at = 26 + 3(1) = 29m/s The units are m/s not m/s^2.
 
Thanks
 
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