Truck vs Tree (first week physics woes)

AI Thread Summary
The discussion revolves around a physics problem where a truck decelerates uniformly at -5.60 m/s² for 4.20 seconds before hitting a tree, leaving skid marks of 62.4 meters. Participants are trying to determine the truck's speed upon impact with the tree. Initial calculations suggest a speed of 10.58 m/s, but further analysis leads to a revised estimate of 26.617 m/s for the initial speed. Final speed calculations indicate the truck strikes the tree at approximately 3.097 m/s. The conversation highlights the importance of correctly applying kinematic equations to solve the problem.
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1. The driver of a truck slams on the brakes when he sees a tree blocking the road. The truck slows down uniformly with an acceleration of -5.60 m/s2 for 4.20s making skid marks 62.4m long that end at the tree. With what speed does the truck strike the tree?

Homework Equations



I'm guessing that I have to use Vf2-Vo2=2as?

I'm really not sure... I've been staring at this problem for hours, is It a trick question? Does it even hit the tree?
 
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You need

<br /> x = x_0 + v_0 t + (1/2) a t^2<br />

you know everyting except for the initial speed.
 
Man i am defenitly going to need to work on knowing which formulas are for which... ummm using that...x=vo2+1/2at2
vo2= x-1/2at2
So vo = square root x-1/2at2square root of 62.4-(-5.6x4.22)/2= 10.573

So he hits the tree at 10.58 m/s?EDIT: Wait did I miss out a t? let me try that again...
 
x-(1/2)at2/t=vo


62.4-(1/2)-5.6x4.22
/4.2

=

26.617 m/s



So that's his initial speed right?

I still don't understand how to get his final speed?
 
Wait V=Vo+at

so 26.617+(-5.6x4.2) = 3.097

does he hit the tree at 3.097 m/s?
 
Be careful with your rearranging. If

x=v_0t+\frac{1}{2}at^2

then

v_0=\frac{1}{t}\Big(x-\frac{1}{2}at^2\Big)=\frac{x}{t}-\frac{1}{2}at
 
I think its just my formating making it look wrong? is 26.617 m/s the right answer?
 
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