- #1

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## Homework Statement

find dy/dx

## Homework Equations

x= tan y

## The Attempt at a Solution

d/dx(x=tanY)

1=(tan(dy/dx))+sec^2+y

- Thread starter jtt
- Start date

- #1

- 16

- 0

find dy/dx

x= tan y

d/dx(x=tanY)

1=(tan(dy/dx))+sec^2+y

- #2

Mark44

Mentor

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First off, you don't take the derivative of an equation - you take the derivative of each side of an equation.## Homework Statement

find dy/dx

## Homework Equations

x= tan y

## The Attempt at a Solution

d/dx(x=tanY)

The above should be d/dx(x) = d/dx(tan(y))

To carry out the differentiation on the right, you need to use the chain rule.

d/dx(f(u)) = d/du(f(u)) * du/dx = f'(u) * du/dx

Nope.1=(tan(dy/dx))+sec^2+y

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