1. Oct 30, 2011 #1

   jtt

   

   1. The problem statement, all variables and given/known data
   find dy/dx
   
   
   2. Relevant equations
   x= tan y
   
   
   3. The attempt at a solution
   d/dx(x=tanY)
   
   1=(tan(dy/dx))+sec^2+y

    

   jtt, Oct 30, 2011
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3. Oct 30, 2011 #2

   Mark44

   

   Insights Author

   Staff: Mentor

   First off, you don't take the derivative of an equation - you take the derivative of each side of an equation.
   
   The above should be d/dx(x) = d/dx(tan(y))
   
   To carry out the differentiation on the right, you need to use the chain rule.
   
   d/dx(f(u)) = d/du(f(u)) * du/dx = f'(u) * du/dx
   

   Nope.

    

   Mark44, Oct 30, 2011

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