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Trying to find dy/dx of a trig function

  1. Oct 30, 2011 #1

    jtt

    User Avatar

    1. The problem statement, all variables and given/known data
    find dy/dx


    2. Relevant equations
    x= tan y


    3. The attempt at a solution
    d/dx(x=tanY)

    1=(tan(dy/dx))+sec^2+y
     
  2. jcsd
  3. Oct 30, 2011 #2

    Mark44

    Staff: Mentor

    First off, you don't take the derivative of an equation - you take the derivative of each side of an equation.

    The above should be d/dx(x) = d/dx(tan(y))

    To carry out the differentiation on the right, you need to use the chain rule.

    d/dx(f(u)) = d/du(f(u)) * du/dx = f'(u) * du/dx
    Nope.
     
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