Trying to find the area between two curves

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SUMMARY

The discussion focuses on calculating the area between a circle of radius 1 and the curve defined by y = |2x|. Participants suggest using integration techniques to find the area under the circle and the triangle formed by the intersection points. The key steps involve determining the equation of the circle, identifying the limits of integration where the circle intersects the triangle, and decomposing the area into manageable sections. The integration should be performed with respect to the x-axis to accurately compute the desired area.

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  • Understanding of integration techniques in calculus
  • Familiarity with the equations of circles and linear functions
  • Knowledge of geometric area calculations, particularly triangles and sectors
  • Ability to identify points of intersection between curves
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  • Learn how to derive the equation of a circle given its radius and center
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Students and educators in mathematics, particularly those studying calculus and geometry, as well as anyone involved in solving area-related problems between curves.

Triathlete
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A circle with radius 1 touches the curve y = |2x| in two places(see attachment for picture). Find the area of the region that lies between the curves.

I am having a tough time with this one. I figured I could put the radius in a spot where it would form a right angle on the line, then try and split the area into two large rectangles, and then subtract the corresponding sectors of the circle from the volume.
Only problem is, there aren't really any numbers so even though I know how to use integration to find the arc length for the sectors, I don't know WHAT to integrate or what my limits of integration would be. I can't seem to find a good place to start. Any help would be appreciated.
 

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I have attached another picture that may better explain my 'game plan'.
 

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Hey Triathlete.

There are (like all problems in mathematics) many ways to do the problem, but one suggestion is to find the equation of the circle and find the difference of the triangle and that of the cone.

Note that if you integrate with respect to the x-axis then what you will get is the area under the circle which will look like a skate-ramp with a block under-neath it.

You can use the idea that the area of the triangle-part can be decomposed from the rectangular part to get the area of the region outside of the triangle.

When you have the area under the circle curve along the x-axis and the region outside the triangle, you take (1) - (2) and you will get the area of the triangle.

So your region of integration will be where the circle intersects the triangle. Then you need to get the equation for your circle so you can find the area under that and the rest relies on splitting up the area in that region to get the triangle separated from the whole rectangle.
 

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