Trying to find the equation of motion of a model

Click For Summary
SUMMARY

The discussion focuses on deriving the equation of motion for a system modeled in a Java application related to oscillations of cylinders. The user is advised to treat the weight force acting at the center of mass of the rod, emphasizing the importance of normal and friction forces in the analysis. Key equations referenced include F=ma, ƩFx=0, and Ʃτ=0, with the user attempting to relate normal forces to the center of mass position over time. The user concludes that the net force on the rod should be expressed as a function of the center of mass displacement from equilibrium.

PREREQUISITES
  • Understanding of Newton's laws of motion (F=ma)
  • Familiarity with normal and friction forces in mechanics
  • Basic knowledge of oscillatory motion and equilibrium
  • Experience with Java applications for physics simulations
NEXT STEPS
  • Research the derivation of equations of motion for oscillating systems
  • Explore the role of friction in dynamic systems, particularly in rotating bodies
  • Study the concept of center of mass and its implications in mechanics
  • Learn about the mathematical modeling of physical systems using Java
USEFUL FOR

Students studying physics, particularly those focused on mechanics and oscillatory motion, as well as developers working on physics simulations in Java.

Broseph
Messages
1
Reaction score
0

Homework Statement


I need to derive an equation of motion for the system modeled in this java app:
http://web.whittier.edu/physweb/lagan/250/ejs_ehu_oscillations_cylinders.jar

I was told to treat the weight force as if it was acting only at the center of mass of the rod, and that normal forces and friction forces are crucial to the problem. I have been playing around with this forever though!

μ is the coefficient of kinetic friction, a is half the distance between the circles.

Homework Equations


F=ma, ƩFx=0, Ʃτ=0

The Attempt at a Solution



Pages and pages of manipulations :p
I tried to mainpulate things to get it to look the way the mass on a spring system looks, so I could say F=C*x, and then just use the fact that f=ma=mx''.
It didn't seem to want to work out that way. I am having trouble finding an equation the relates the normal forces to the position of the center of mass at time t. ( the x(t) ). I now that when the displacement of the center of mass from the resting position is zero, then the normal forces are equal. i think that the normal force on the left side = mg/2 * (a-x(t))/a and the right side = mg/2 * (a+x(t))/a. (remember a is half the distance between the cylinders in the app)
 
Last edited by a moderator:
Physics news on Phys.org
You should be able to write down the net force on the rod as a function of the displacement of the center of mass from equilibrium. With that expression it should be down hill from there.

A first guess is the force on the rod is proportional to the displacement? Complications might arise if the rotating cylinders were rotating slow enough to the point that friction force on one cylinder changed direction?
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
2K
Replies
7
Views
1K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
24
Views
3K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 11 ·
Replies
11
Views
3K