Taking a look at "http://www.space.com/30026-earth-twin-kepler-452b-exoplanet-discovery.html" I observe that planet Kepler-452b (judged to be somewhat Earth-like) is 1400 light years from Earth. If a spaceship leaves Earth at a fifth of the speed of light, traveling toward Kepler-452b, from Earth's perspective it will take 7000 years to get to its destination. Or, perhaps better stated, if the spaceship sends a signal from Kepler-452b the moment it arrives there, and the signal travels at the speed of light, Earth observers will receive the signal 8400 years after the spaceship left Earth. But using the formula for the Lorentz factor on "https://en.wikipedia.org/wiki/Lorentz_transformation" I get gamma = 1 / sqrt( 1 - v^2/c^2) which would be gamma = 1.02062, which would mean to astronauts on the spaceship it would appear that the trip to Kepler-452b took 6858.57 years, right? On the other hand, if the spaceship traveled at .3c instead of the .2c of the previous example, from Earth's frame of reference the trip would take 4666.7 light years (by the same reckoning as above, a signal sent out from the spaceship upon arriving would reach the Earth 6066.7 years after the spaceship left). But now the Lorentz factor would have gamma be 1.04828, so the duration of the trip from the frame of reference of the astronauts on the ship would be 4451.72 years, correct? I'm just trying to get a feel for how the Lorentz Transformation affects how an astronaut perceived time as her/his spaceship traveled at speeds close to the speed of light.