Tsunami word problem (waves practice)

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SUMMARY

The discussion focuses on calculating various properties of a tsunami wave generated 4000 km offshore California, with a sea surface displacement of 3 meters and a wavelength of 100 km. The wave is identified as a shallow water wave, leading to a calculated speed of approximately 198 m/s and an estimated travel time of about 20203 seconds to the shore. The frequency is determined to be 505.1 Hz, with a period of 1.97 ms. As the wave approaches shallower depths, the new wavelength is recalculated to approximately 5051 m, while the amplitude changes due to the conservation of energy flux.

PREREQUISITES
  • Understanding of wave mechanics, specifically shallow water wave theory
  • Familiarity with the equations for wave velocity, frequency, and period
  • Knowledge of energy conservation principles in wave dynamics
  • Basic proficiency in calculus for solving wave equations
NEXT STEPS
  • Study the derivation and application of the shallow water wave velocity formula, Cp = √(gh)
  • Learn about the conservation of energy in wave mechanics and its implications on amplitude
  • Explore the relationship between wave speed, wavelength, and frequency in varying depths
  • Investigate wave power calculations and their relevance to tsunami energy dynamics
USEFUL FOR

Students and educators in physics, oceanography, and environmental science, as well as engineers and researchers involved in tsunami modeling and wave energy studies.

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Homework Statement


A Tsunami has been generated as a plane wave 4000km off the shore of California. The sea surface displacement is found to be 3 meters and the wavelength of the tsunami is 100km. You can assume a depth of 4000m from the location of wave generation to shore.

a.) Calculate the speed of the wave (assume it is a deep water wave if h/lambda > 1/4 and it is a shallow wave if h/lambda < 1/20) Estimate the time it will take this wave to reach the shore.

b.) calculate the frequency and period of the tsunami

c.) As the wave approcahes the shore its depth decreases from 4000m to 10m. What is it's new wavelength? (the wave period is conserved as the depth changes)

d.) What is the new amplitude of the wave? (you must conserve energy flux)


Homework Equations


shallow water wave velocity Cp = √gh
frequency = Cp/λ
Period = 1/F


The Attempt at a Solution



Part a is pretty easy. IT is a shallow water wave because h/λ < 1/20. The wave velocity is [(g)(h)]^1/2 which equals ~198m/s. Given the offshore distance of 4000000m, it would take a time of (4E6m/197.99m/s)= 20203 s.

PArt b is also straight forward: The frequency is F= Cp/λ which equals (198m/s)/(100000m) = 505.1 Hz. The period T = 1/F or 1.97E-3 s

Part c is what I'm having trouble on. if the wavelength λ=Cp/F and the period is conserved, does that mean the frequency is also conserved? So does this simply become (198m/s)/505.1s = 0.39m? Or do I need to recalculate Cp with a depth of 10m?

Cp= [(g)(10m)]^1/2 = ~10m/s so then wavelength would be (10m/s)(505.1Hz)= 5051m?

Also, I'm not sure about part d. If I were to guess, I would use
E= (1/2)ρga^2
But I can't see how amplitude would change here, because ρ and g are constant!

Help!
 
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Better check the calc for frequency in (b); looks like you inverted it or something.
Yes, the speed changes as the water gets shallow.
The amplitude is related to the power and energy of the wave. It says energy is conserved, so you must have the same power in the shallow wave as in the ocean wave. If you don't have a formula for water wave power, you might check
http://en.wikipedia.org/wiki/Wave_power
The power depends on the period and amplitude, so if power stays constant amplitude will change when it goes shallow.
 
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