Twin Paradox Explained: Earth & Space Time Effects

manimaran1605
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A person in the Earth (stationery frame) observes the clock in the spaceship (which almost moving at the speed of light) runs slow right? and an astronaut in the space-ship observes the clock in the earth, to him the clock also appears slow the same rate as the person observes the clock in the spaceship right? Then how does the Twin Paradox works?
 
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Try a forum search. That's only been discussed here about a thousand times.
 
You haven't got to the "paradox" bit yet. The astronaut needs to turn around and return to the earth. The process of turning round is what makes the traveller older when he gets back.
You should really read this, and then ask a more specific question if you are still unclear.
http://math.ucr.edu/home/baez/physics/Relativity/SR/TwinParadox/twin_paradox.html
 
m4r35n357 said:
You haven't got to the "paradox" bit yet. The astronaut needs to turn around and return to the earth. The process of turning round is what makes the traveller older when he gets back.

s/older/younger/

Sorry for that!
 
Hi、manimalan 1605. You are right if they do not meet again. One of them at least has to leave his original frame of inertia to see his brother.
 
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ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...

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