Confusedent
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I'm going to test my understanding by taking a crack at this one... plus I'd already been thinking about this situation some...
Yes, they are the same age, and its not inconsistent because of relative simultaneity. Events happening simultaneously for observers in the galaxies reference frame will happen non-simultaneously and in opposite orders for the two observers (since the Lorentz transformation between two events depends on v and not v^2, the sign reverses the order of t1 and t2). So a greater amount of time can pass for one observer between one event and when they meet than for the other and the same event, allowing for each to determine that the other is the slower aging one. For example, observers in the reference frame of the galaxies would determine that each traveller was born (or passed their starting galaxy) at the same time, while each traveller in their reference frame would determine the other had "started" at an earlier time, in order to have aged at a slower rate and been the same age when meeting. I believe this makes sense because each traveller, seeing themselves as stationary, would determine the other traveller to be the one suffering from relativistic addition of velocities relative to the galaxies (each sees the galaxies as moving at .8c, while seeing the other observer moving at some .8c < v < c), hence each sees the other observer as "losing" some speed relative to the galaxies (moving slower relative to them than himself). If one observer sees the other as having traveled the same distance, but having taken longer to do it, then he must judge that the other observer moved slower relative to the galaxies than he did (since in that reference frame he started earlier).
I hope that was atleast halfway correct and somewhat readable.
I'm going to say no, because again each sees themselves as the stationary one, so each sees the others as aging slower. They cannot meet and determine that each is actually younger, so on meeting at Galaxy B all will determine they are the same age, but will disagree about who passed their starting galaxy first. The reasoning was all explained in the last paragraph.
nutgeb said:When the twins pass very close by each other (say, within 10 meters) at Galaxy B they can communicate with each other and see into the other ship's window. Will they agree that their ship clocks are synchronized with each other then?
Special Relativity says that an observer in any inertial frame will measure her own clock ticking slower than a clock in an inertial frame which is in motion relative to the observer's rest frame (at relativistic speed). So is there a paradox when the ships pass by each other and each twin can look in the window of the other ship and observe that the other twin has not aged differently than herself?
Yes, they are the same age, and its not inconsistent because of relative simultaneity. Events happening simultaneously for observers in the galaxies reference frame will happen non-simultaneously and in opposite orders for the two observers (since the Lorentz transformation between two events depends on v and not v^2, the sign reverses the order of t1 and t2). So a greater amount of time can pass for one observer between one event and when they meet than for the other and the same event, allowing for each to determine that the other is the slower aging one. For example, observers in the reference frame of the galaxies would determine that each traveller was born (or passed their starting galaxy) at the same time, while each traveller in their reference frame would determine the other had "started" at an earlier time, in order to have aged at a slower rate and been the same age when meeting. I believe this makes sense because each traveller, seeing themselves as stationary, would determine the other traveller to be the one suffering from relativistic addition of velocities relative to the galaxies (each sees the galaxies as moving at .8c, while seeing the other observer moving at some .8c < v < c), hence each sees the other observer as "losing" some speed relative to the galaxies (moving slower relative to them than himself). If one observer sees the other as having traveled the same distance, but having taken longer to do it, then he must judge that the other observer moved slower relative to the galaxies than he did (since in that reference frame he started earlier).
I hope that was atleast halfway correct and somewhat readable.
nutgeb said:During the inertial (constant speed) phase of the trip did both twins age less than the residents of the 3 relatively "stationary" galaxies?
I'm going to say no, because again each sees themselves as the stationary one, so each sees the others as aging slower. They cannot meet and determine that each is actually younger, so on meeting at Galaxy B all will determine they are the same age, but will disagree about who passed their starting galaxy first. The reasoning was all explained in the last paragraph.