Question related to post #26/Granpa
This response references post #26 so apologises for being so out-of-sync with the current exchanges. However, an aspect of this thread was raised in another thread entitled `
Gravitational Redshift`, which touched on a triplet extension to the twin paradox – outlined below.
I was particular interested in the link given in #26.
http://www.sysmatrix.net/~kavs/kjs/addend4.html
Initially I thought this link was trying to explain how 2 frames of reference could both justify how time was running slower in the other frame. Having now having had a chance to take a closer look at the detail, I don’t believe the example supports such a conclusion. While it may resolve the time difference between the 2 frames, it is clear at the start and end of the journey that only 1 frame was moving with respect to the other and it was this frame that underwent time dilation.
Note: There is no inference of an absolute frame of reference being made in this statement, simply that because there is an unambiguous start/stop point, where the frames recombined, there is no ambiguity of relative velocity or time dilation.
The triplet variant, mentioned above, is just an extension of the twin paradox. However, while 1 triplet stays on Earth, the other 2 take identical journeys at the same relative speed (and acceleration), as each other with respect to the stay-at-home triplet, but always in the opposite direction, i.e.
Triplet-1: A
Triplet-2: A-B-A-C-A
Triplet-3: A-C-A-B-A
Calculations, based on special relativity, seem to suggest that triplet 2 & 3 both measure the same elapsed time, which is less than triplet-1, at the end of the journey. However, there is a point in the journey above, when triplets 2 & 3 pass each other, as well as triplet-1, at point (A), where all have a relativistic velocities with respect to each other. This suggests that triplets 2 and 3 must experience some relativistic time dilation, with respect to each other, while the overall suggestion is that triplets 2 and 3 mark the same time throughout the journey with respect to triplet-1.
http://math.ucr.edu/home/baez/physics/Relativity/SR/TwinParadox/twin_vase.html#doppler
The link above outlines both the Doppler Shift and GR explanations of the twin paradox based on a relative velocity of 0.866c giving \gamma=2. As such, it is the
‘stationary’ twin that transmits twice as many light pulses and the
‘moving’ twin. It can be seen that the
‘moving’ twin always receives twice as many pulses than it transmits over the entire journey due to the effects of time dilation. While the change in relative velocity makes the arrival rate complex, it is not impossible to calculate exactly when the pulses will arrive, assuming that the time dilation is a constant ongoing effect.
So finally, applying this same analysis to the triplet example, it seems to suggest that time for triplets 2 and 3 runs at the same rate throughout the journey, which is only time dilated with respect to triplet-1. If so, it suggests that no ‘
physical or meaningful’ time dilation takes place as triplets 2 and 3 pass each other at 0.866c+0.866c=0.99c. Therefore, would be interested in any other interpretations.