Two bodies moving from point A

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Two bodies start moving from point A at different times and speeds, with one body accelerating by 6 m each minute and the other by 3 m. The first body moves at 3 m/min initially, while the second starts 5 minutes later at 54 m/min. The poster initially attempted to use the distance formula but struggled with the arithmetic progression involved in the problem. They realized that the increasing distance per minute for the first body should not be treated as constant acceleration. The discussion highlights the complexity of applying physics equations to scenarios involving variable speeds.
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Homework Statement



One body starts moving from point A so that in first min it goes 3 m/min, and in every next minute it goes 6 m more that in the minute before. Another body starts moving from point A 5 minutes later, going 54 m/min in the first minute and in every other minute 3 m more that in the minute before. After how many minutes have the bodies traveled the same distance? (Time starting after the second body starts its movement.)

Homework Equations



s=v0t+at2/2

where s - distance
v0 - initial velocity
a - acceleration
t - time

The Attempt at a Solution



I already know how you can solve this using arithmetic progression. But what I can't understand is why doesn't the distance equation from physics apply in this. It ought to!

So what I did was this:

s1=s2

s1=3(t+5)+6(t+5)2/2
s2=54t+3t2/2

3(t+5)+6(t+5)2/2=54t+3t2/2

t=1,5t2-21t+75,

which doesn't work out. What am I doing wrong here?

Thanks in advance,
fawk3s
 
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Ok, I think I figured it out now. I guess you can't take those "goes 6 m more in the next minute" as an acceleration.
This thinking made my head hurt :(
 
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