Two builders carry a sheet of drywall up a ramp. Assume that W=1.80 m, L= 3.30m, and that the lead builder carries a vertical weight of 183.0 N (41.1 lbs). What is the vertical weight carried by the builder at the rear?
The builder at the rear gets tired and suggest that the drywall should be held by its narrow side. What is the weight he must now carry?
Fy = 0
The Attempt at a Solution
Well I don't have a godd idea as to how to do this and what I am doing.
First I said Fy= F1 + F2 - W= 0
torque = F2*l2 - Wlw = 0
l2= 3.30 cos 25
lw= .75 cos 25
W= F2(l2/lw)= 183 N (3.30 cos 25/ .75 cos 25)
W= 805.2 N
F1= W-F2 = 805.2 - 183 = 622.2 N
However my answer is wrong. Since I can't get the first part correct I haven't moved on to the second.
What am I doing wrong?