Two converging lens, find the final image....

In summary, the final image position in a system of two converging lenses is determined by the combined effect of the individual lenses, where the light rays from the second lens converge. The final image distance can be calculated using the lens equation and is the distance from the second lens to the final image. Moving the two lenses closer together will result in a closer final image due to an increase in overall power. The final image can be virtual if the first lens forms a virtual image. The magnification of the final image is the product of the individual lens magnifications and can be calculated using the equation -d<sub>i</sub>/d<sub>o</sub>.
  • #1
AdkinsJr
150
0

Homework Statement

lens problem.PNG


Homework Equations



[tex]\frac{1}{p}+\frac{1}{q}=\frac{1}{f}[/tex]

The Attempt at a Solution


I already had this typed in word so here is a screen shot:
attempt....PNG


I don't understand why the negative is omitted in the "correct answer" "B." In solving this problem I wanted to proceed in finding the image location relative to the first lens, which should be 9.2 cm.
 
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  • #2
The diagram does not define the axes so the sign is arbitrary.
 

1. How is the final image position determined in a system of two converging lenses?

The final image position in a system of two converging lenses is determined by the combined effect of the individual lenses. The first lens forms an intermediate image, which then serves as the object for the second lens. The final image position is where the light rays from the second lens converge.

2. How do you calculate the final image distance in a system of two converging lenses?

The final image distance can be calculated using the lens equation, which is given by 1/f = 1/do + 1/di, where f is the focal length of the lens, do is the object distance, and di is the image distance. In a system of two lenses, the object distance is the distance from the first lens to the object, and the image distance is the distance from the second lens to the final image.

3. What happens to the final image when the two converging lenses are moved closer together?

When the two converging lenses are moved closer together, the final image will move closer to the lenses. This is because the combined effect of the lenses is to increase the overall power of the system, resulting in a shorter focal length and a closer image distance.

4. Can the final image in a system of two converging lenses be virtual?

Yes, the final image in a system of two converging lenses can be virtual. This can occur when the first lens forms a virtual image, which then becomes the object for the second lens. In this case, the final image will also be virtual and will appear on the same side of the second lens as the object.

5. What is the magnification of the final image in a system of two converging lenses?

The magnification of the final image in a system of two converging lenses is the product of the magnification of each individual lens. This can be calculated using the equation m = -di/do, where di is the image distance and do is the object distance for each lens. The overall magnification will depend on the relative positions and magnifications of the two lenses.

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