Two-Dimensional Perfectly Inelastic Collisions

AI Thread Summary
In a two-dimensional perfectly inelastic collision, the final velocity of the wreck can be determined using conservation of momentum in both the x and y directions. The initial momenta of the truck and van must be calculated by resolving their velocities into components based on the angles of their respective roads. The total momentum before the collision is equal to the total momentum after the collision, allowing for the calculation of the final velocity vector. The lack of provided equations has led to confusion, but understanding the component resolution is crucial for solving the problem. The final velocity can then be derived from the combined momentum of both vehicles at the point of impact.
scoop91
Messages
4
Reaction score
0
A 25000 kg truck moving at 40 m/s on a road angled at 17° hits a 10000 kg van moving at 25 m/s on a road angled at 60° at an intersection between two the two roads. Since this is a two-dimensional perfectly inelastic collision, what is the final velocity of the wreck?


Not sure about which equation to use



Attempt at solution: Instantly stuck. Our professor did not give us the equation for two-dimensional perfectly inelastic collision.
 
Physics news on Phys.org
Thinking about any 2 dimensional problem such as kinematics, what is usually the first step when dealing with components that are not resolved in x and y directions?
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanged mass'

Thread 'A cylinder connected to a hanged mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Perfectly inelastic collision of two moving and rotating disks
Replies
9
Views
2K
Inelastic Collision: Finding Initial Angle
Replies
22
Views
4K
Inelastic collision with an inclined plane
Replies
7
Views
4K
Initial velocity in an inelastic collision
Replies
4
Views
2K
Elastic and inelastic collisions
Replies
4
Views
3K
Inelastic Collision of drunken driver
Replies
7
Views
2K
Velocity and Direction of a System after Inelastic Collision
Replies
2
Views
2K
What is the Solution to a Perfectly Inelastic Collision Problem?
Replies
2
Views
3K
Acceleration in One Dimensional Inelastic Collision
Replies
33
Views
4K
Zero momentum reference frame and an inelastic collision
Replies
4
Views
3K

Hot Threads

Recent Insights

Back
Top