Two E. Bound RR Cars Collide: What Happens Next?

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The collision of two railroad cars, one weighing 20,000 lbs at 5 ft/sec and the other 40,000 lbs at 7.81 ft/sec, results in them coupling together and moving with a common velocity. Using the conservation of momentum, the total momentum before the collision is calculated by adding the individual momenta of both cars. After the collision, the combined mass of the cars is used to determine their new velocity. The final velocity can be derived from the equation p = mv, ensuring that momentum remains constant in the system. The analysis demonstrates the principles of momentum conservation in a collision scenario.
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A railroad car that weighs 20,000 lbs. is traveling eastward with a velocity whose magnitude is 5 ft./sec. A second car, on the same track, that weighs 40,000 lbs. is also traveling in an easterly direction with a velocity of 7.81 ft./sec. When the cars collided, they became coupled together and then both cars moved with the same velocity. If friction between the cars and the rails is neglected, what were the magnitude and the direction of the velocity of the cars after the collision?
 
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You can use conservation of momentum. Momentum in a closed system is always a constant. To calculate momentum use p = mv (p = momentum, m = mass, v = velocity). As they are coupled together after the collision, you are just taking the combined mass and using the momentum from before the collision (work out the momentum of each car and add them) to work out v.
 


wow thanks for your big help
 
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