Two Hanging mass's attached to one on the table

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The discussion revolves around calculating the acceleration of a 2.0 kg block on a table with a coefficient of kinetic friction of 0.350. The user attempted to find the acceleration by considering the tensions from two hanging masses and the normal force acting on the block. However, the calculation was incorrect due to neglecting the left side tension in the net force equation. The correct approach requires incorporating all forces acting on the block to accurately determine the acceleration. Assistance is sought to resolve the calculation error.
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Homework Statement


The coefficient of kinetic friction between the 2.0 kg block in figure and the table is 0.350.

What is the acceleration of the 2.0 kg block?

Homework Equations


F=uK*Force Normal
Fnet=ma

The Attempt at a Solution


I tried to take the mass's of both the hanging and used them to calculate a net force on the block in the center and then solved for acceleration that way. Here's my work.

3kg*9.8=29.4N Right Side Tension
1kg*9.8=9.8N Left Side Tension
2kg*9.8=19.6N Force Normal

F=.35*19.6N
6.86N

(29.4N-6.86N)-9.8N=2kg*acceleration

a=6.34m/s^2

and it turns out this is wrong please help me out thank you!

-Charan
 

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You forgot the left side tension...
 

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Thread 'A cylinder connected to a hanging mass'

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