(adsbygoogle = window.adsbygoogle || []).push({}); 1. How many celsius degrees does the temperature of a mass of 1.00 kg of water fall for each 83.8 kJ of heat it loses.

2. Not so sure about EQUATIONS but I have my own way of going at it.

3. 83.8 kJ / 4.19 J * (1.00 kg * 1000) = 0.2 degrees celsius

1. How much heat is required to raise the temperature of a mass of 10.0 kg of water a total of 20.0 celsius degrees.

2. Not so sure about EQUATIONS but I have my own way of going at it.

3. IF it takes 4.19 j of heat to raise the temperature of 1 gram of water by one degree celsius, how do we factor in the larger mass of 10,000 grams and the larger temperature change of 20 celsius degrees?

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# Homework Help: Two heat/temperature problems

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