I think I see the problem ... you mean:
why is the singlet state not the ground state?
It's tricky to explore in various course notes: i.e.
http://physicspages.com/2013/03/08/infinite-square-well-2-particle-systems/
... where they say the ground state is n1=1, n2=2
vs this:
http://www.st-andrews.ac.uk/physics/quvis/embed_item_3.php?anim_id=48&file_sys=index_phys
GS has n1=n2=1 but spins are opposite.
A lecture that kinda covers both views is:
http://physics.uwyo.edu/~yurid/QM/Lecture%2017.pdf
...
without considering spins, the |1,1> combined state does not exist - so the ground state is a triplet state.
Singlet state description is covered later.
It would be nice if the author made a definitive statement about the resulting ground state.
See also in these forums - pretty much the same question:
https://www.physicsforums.com/showthread.php?t=393603
I'm wondering if there is an unspoken assumption in the context of the problem.
One possibility is that some sources consider "noninteracting" to mean the fermions cannot see each other's spin - so the spin component of the wavefunction has no effect. In order for indistinguishable non-interacting spinless fermions to follow fermi-dirac statistics, the space wavefunction must be antisymmetric. It's when they start glibly referring to "electrons" that bothers me - atomic subshells clearly have 2 electrons each.
I don't see anything wrong with the GS being the singlet, off the top of my head.