Two Level System - Finding Energy as a function of Temperature

gysush
Messages
22
Reaction score
0
Consider a two level system of N distinguishable particles. We want to find the Energy of the system as a function of the Temperature. The first energy level is E1 and the second is E2.

I computed the entropy. Now if we take a derivative with respect to Energy, we have

1/T = dS/dE where S = f(N,N1) or f(N,N2) depending on how we substitute.

Consider another problem, namely dipoles in a uniform magnetic field, then
E=M*Eo , where M = N+ - N-

Then, 1/T = dS/dE= 1/Eo*dS/dM

We can easily calculate dS/dM and rearrange stuff.

The problem I'm having is how to take dS/dE when E=N1*E1 + N2*E2.
 
Physics news on Phys.org
One way to do it is to use the chain rule. For example:

\frac{dS}{dE} = \frac{dS}{dN_1} \frac{dN_1}{dE}

Note that since the total number of particles is constrained to be N, you have that

E = N_1 E_1 + (N-N_1)E_2~\mbox{or}~(N-N_2)E_1 + N_2E_2.

That is to say: You can choose either N1 or N2 to be your only variable. Of course, at the end, you'll have to put everything back in terms of energy at the end of the problem, so don't forget to do that if you want to solve for E(T).
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top