Two masses connected by strings on an incline

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SUMMARY

The discussion focuses on calculating the tension in two strings connected to two masses on a frictionless incline. For mass m1 = 9.0 kg and mass m2 = 3.9 kg, the tension in string 1 (T1) is determined to be 30.2 N. The participant struggled with the calculations, particularly in breaking down the forces and using free body diagrams effectively. The solution involves understanding the components of tension and gravity acting on the masses.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of free body diagrams
  • Familiarity with vector components of forces
  • Basic trigonometry for resolving forces
NEXT STEPS
  • Study the concept of free body diagrams in physics
  • Learn how to resolve forces into their vector components
  • Explore the principles of tension in strings and pulleys
  • Review problems involving inclined planes and frictionless surfaces
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This discussion is beneficial for physics students, educators, and anyone seeking to understand the mechanics of forces on inclined planes, particularly in the context of tension in strings.

David Mordigal
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This is a problem from my physics homework. I copied the diagram below as best I could from the text. It's not the best rendering but you'll get the idea.

1. Homework Statement

Two blocks are at rest on a frictionless incline, as shown in the figure.
xLdW8Sg.png

Part A. What is the tension in the string number 1 if m1 = 9.0kg and m2 = 3.9kg?
Part B. What is the tension in the string number 2 if m1 = 9.0kg and m2 = 3.9kg?

The answer to Part A is: T1 = 30.2 N, which I don't understand.

Homework Equations


So far, I know the following:
F = ma
Fx = max
Fy = may
w = wy = mg = 9.0kg * 9.8 m/s2 = 88.2 N

The Attempt at a Solution


I tried splitting the tension of string 1 into its vector x and y components, but that wasn't getting me to the right answer. I am not quite sure where to start or how they got that answer, 30.2 N (part A). Any guidance would be much appreciated.

Ty = mg = 88.2 N
T = Ty/sin(20) = 257.9 N
 
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Hi David welcome to PF.
I suggest you to choose your co-ordinate axis as shown in figure.
After drawing free body diagrams of m1 can you find T1?
 
It does work to have the axes so gravity points in the -y direction ... but, as Satvik suggests, the maths is way easier if you point the x-axis along the slope. The reason you are having trouble is probably because you have not included all the forces on each mass ...

The first step is always to draw a free body diagram - make it a habit.
Please tell us what forces you put on it and where they point.
 

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