Two objects launched into the air by identical springs

  • Thread starter Thread starter fattydq
  • Start date Start date
  • Tags Tags
    Air Springs
AI Thread Summary
Two objects of different masses launched by identical springs will leave the springs with the same energy, as the spring's energy formula does not depend on mass. However, they will not reach the same maximum height, as the lighter mass will ascend higher due to its lower weight. The kinetic energy of each mass will differ because it is calculated using the mass and velocity, which are both affected by the spring's energy. The discussion highlights that while both masses leave the springs with the same energy, their resulting kinetic energies and maximum heights will vary. Ultimately, the lighter mass gains more gravitational potential energy than the heavier mass due to its greater height.
fattydq
Messages
79
Reaction score
0
Two objects with DIFFERENT MASSES are launched vertically into the air by identical springs. The two springs are compressed by the same distance before launching. Which of the following statements is or are true? (NOTE: THERE MAY BE MORE THAN ONE TRUE STATEMENT).
A) Both masses reach the same maximum height
B) Both masses leave the springs with the same energy
C) Both masses leave the springs with the same speed
D) Both masses leave the springs with the same Kinetic Energy
E) The lighter mass will gain more gravitational potential energy than the heavier mass.

this actually isn't a homework question, but it's posed at the beginning of a chapter in my book and I'm trying to work through it and figure it out before I read the chapter, kind of to challenge myself, since I have no other homework tonight : )

I know I can rule D out immediately, since the formula for kinetic energy directly involves multiplying by mass, and thus I can rule B out right? I also think I can rule A out, just due to common sense (if a spring were launching an elephant and a ping pong ball, the elephant might barely move while the ping pong ball would fly into the air)

For E I thought it was the opposite? Wouldn't the heavier mass gain more potential energy?

So I think I'm left with C...I could be terribly wrong though and I'd love to discuss this with you guys!
 
Physics news on Phys.org
since the equation for the energy of a spring is .5kx^2 and doesn't involve mass, one could say the masses leave the springs with the same energy. and for part E the potential energies would be the same since kx^2 is directly proportional to mgh---increasing mass would only decrease height proportionally and vice versa
 
ill said:
since the equation for the energy of a spring is .5kx^2 and doesn't involve mass, one could say the masses leave the springs with the same energy. and for part E the potential energies would be the same since kx^2 is directly proportional to mgh---increasing mass would only decrease height proportionally and vice versa

Ahh that makes sense, thanks, I forgot to consider that equation for the energy of a spring.

So B and C are viable, yes? Any other notes of interest in this problem?
 
Not so fast on ruling out D..
Yes, KE= .5mv^2, and the masses are different,but the speeds at which they are launched at are also different, which could give you the same KE product..
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top