Two small insulating spheres with radius

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To calculate the electric field at the midpoint between two insulating spheres, one negatively charged (-2.20 μC) and the other positively charged (4.05 μC), the relevant formula is E = Q/(4πε₀r²). The distance used should be the center-to-center distance divided by two, not the radius of the sphere. It is important to convert microcoulombs to coulombs for accurate calculations. The radius of the sphere does not affect the electric field calculation in this scenario.
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Homework Statement



Two small insulating spheres with radius 5.50×10−2 m are separated by a large center-to-center distance of 0.510 m. One sphere is negatively charged, with net charge -2.20 \mu C, and the other sphere is positively charged, with net charge 4.05 \mu C. The charge is uniformly distributed within the volume of each sphere.

Calculate E_1, the magnitude of the electric field at the midway point due to the sphere with charge -2.20 \mu C only.

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The Attempt at a Solution


I tried to use q/4pi(espolon not)r^2 but I am not sure my radius is right because I have used half the distance for the distance and the radius of the sphere for the distance.
 
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E(sphere) = Q/ 4pi(distance)^2
Notice that this the same as a point charge. You do not need to worry about the radius of the sphere for this part of the question.
 
thanks

my problem was that I wasn't changing my units from micro coulombs to coulombs.
 
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