Two spinning disks, did I mess up?

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The discussion revolves around the interaction of two uniform disc-shaped gears with different radii and moments of inertia. The larger gear, initially spinning at a certain angular speed, experiences a torque that is twice as strong as that on the smaller gear when they mesh. The initial calculations incorrectly assumed a direct relationship between the angular momentum changes, leading to a miscalculation of the final angular speed. The realization that both the mass and moment of inertia are quadratic in radius clarified the misunderstanding, confirming that the larger gear's angular speed should indeed decrease by 20%. The participant acknowledges the error and expresses appreciation for the problem's complexity.
etotheipi
Homework Statement
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Relevant Equations
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Hey guys, I need to check that I'm not doing something stupid. You have two uniform disc-shaped gears, one of which has twice the radius of the other [and 16 times the moment of inertia]. Initially, the larger gear is spinning at ##\omega##, and then they're suddenly meshed together. We need to show that the angular speed of the larger disk drops by 20%. [Edit. To clarify, the disks are given to have equal uniform area densities ##\sigma##].

Since the torque of the tangential force on the larger disk about its centre is twice in magnitude compared to the torque of the tangential force on the smaller disk about its centre, I reckoned that the change in angular momentum of the larger one would be twice that of the smaller one, i.e. that ##16(\omega - \omega_f) = 2\omega_f##. But that gives me that ##\omega_f = (8/9)\omega##, which clearly isn't a 20% decrease.

What did I miss?! It's almost completely improbable that the question contains a mistake, so the error must be on my end. Thanks!
 
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16 times the moment of inertia? Its quadratic in the radius.
 
hutchphd said:
16 times the moment of inertia? Its quadratic in the radius.

But the mass of the uniform disk is also quadratic in the radius, so the product ##I = (1/2)mr^2 = (1/2) \pi r^2 \sigma r^2 = (1/2) \pi \sigma r^4## is quartic in the radius. I should have specified that both are given to have equal area densities ##\sigma##, and not equal masses. This part is in agreement with the given solutions.
 
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I see it. The larger gear will get twice the torque impulse as you notice. But it will also be spinning twice as fast as the big gear ...so that should be ##2(2\omega_f)## on the RHS of the equation.
I believe I have violated the "homework rule".
 
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hutchphd said:
I see it. The larger gear will get twice the torque impulse as you notice. But it will also be spinning twice as fast as the big gear ...so that should be ##4\omega_f## on the RHS of the equation.
I believe I have violated the "homework rule".

That’s it, thanks :wink:
 
This was a really interesting problem.
 
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