Two springs and the energy question

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The discussion revolves around calculating the total mechanical energy and the speed of a stone in a horizontal slingshot system with two identical springs. The total mechanical energy is derived from the potential energy stored in the springs when pulled from equilibrium, with a calculated value of 3.127 J. The speed of the stone at the equilibrium position is determined to be 2.274 m/s. Participants clarify that the energy stored in the springs should be calculated based on the stretch from equilibrium, not the overall length. The confusion about whether the springs are in parallel or series is addressed, emphasizing the need to focus on the amount of stretch for accurate calculations.
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Homework Statement



A horizontal slingshot consists of two light, identical springs (with spring constants of 24.1 N/m) and a light cup that holds a 1.21-kg stone. Each spring has an equilibrium length of 50 cm. When the springs are in equilibrium, they line up vertically. Suppose that the cup containing the mass is pulled to x = 0.7 m to the left of the vertical and then released. Determine

a) the system’s total mechanical energy.


b) the speed of the stone at x = 0.




Homework Equations





The Attempt at a Solution

 

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welcome to pf!

hi coldpay! welcome to pf! :wink:

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
i know the the total mechanical energy is mgh plus 0.5kx^2 but i can't find the answer.

answers
a)3.127 J
b)2.274 m/s
 
coldpay said:

Homework Statement



A horizontal slingshot consists of two light, identical springs (with spring constants of 24.1 N/m) and a light cup that holds a 1.21-kg stone. Each spring has an equilibrium length of 50 cm. When the springs are in equilibrium, they line up vertically. Suppose that the cup containing the mass is pulled to x = 0.7 m to the left of the vertical and then released. Determine

a) the system’s total mechanical energy.


b) the speed of the stone at x = 0.




Homework Equations





The Attempt at a Solution


coldpay said:
i know the the total mechanical energy is mgh plus 0.5kx^2 but i can't find the answer.

answers
a)3.127 J
b)2.274 m/s

I don't think the mgh term will change by pulling back the slingshot. Calculate how much energy is stored in the springs as they are pulled from their equilibrium postition back to the position shown. Show us your work please.
 
X=√0.5^2+0.7^2=0.86

0.5kx^2=0.5*48.2*(0.86)^2=17.34 i found this but i am not sure if the spring is parallel or serial(i take it parallel)

This is all i can do.I don't know the rest of the question.
 
coldpay said:
X=√0.5^2+0.7^2=0.86

0.5kx^2=0.5*48.2*(0.86)^2=17.34 i found this but i am not sure if the spring is parallel or serial(i take it parallel)

This is all i can do.I don't know the rest of the question.

In the spring equation, the "X" is meant to be the amount of stretch, not the overall length.
 
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